1.

For the reaction Ni^(2+) +4NH_(3) iff [Ni(NH_(3))_(4)]^(2+), at equilibrium, if the solution contain 1.65xx10^(-4)% ofnickel in the free state, and the concentration of NH_(3) at equilibrium is 0.5 M. Then the instability constant of the complex will be approximately equal to :

Answer»

`1.0xx10^(-5)`
`1.5xx10^(-16)`
`1.0xx10^(-7)`
`1.5xx10^(-17)`

SOLUTION :`NI^(2+)+4NH_(3) iff [Ni(NH_(3))_(4)]^(2+)"":. K=([Ni(NH_(3))_(4)]^(2+))/([Ni^(2+)[NH_(3)]^(4)])`
But ` ([Ni^(2+)])/([Ni^(2+)]+[Ni(NH_(3))_(4)]^(2+))=1.6xx10^(-6)`
`or (Ni^(2+))/([Ni(NH_(3))_(4)]^(2+))~~1.6xx10^(-6)"":. K=(10^(6))/(1.6xx(0.5)^(4))=10^(7)`
Hence instability constant`=10^(-7)`


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