1.

For the reaction Ni^(2+)+4NH_(3) to [Ni(NH_(3))_(4)]^(2+), at equilibrium is 0.5M. Then the instability constant of the complex will be approximately equal to :

Answer»

`1.0xx10^(-5)`
`1.5xx10^(-16)`
`1.0xx10^(7)`
`1.5xx10^(-17)`

Solution :`K_(3)=(100)/(1.6xx10^(-4)XX(0.5)^(4))`
`K_("INS")=(1)/(K_(s))=1.6xx(0.5)^(4)xx10^(6)=10^(7)`


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