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For the reaction , `O_2(g)+2F_2(g)to2OF_2(g),K_p=4.1` If `P_(O_2)(g)=0.116` atm and `P_(F_2)(g)=0.0461` atm at equilibrium , what is the pressure of `OF_2(g)`?A. 0.101 atmB. 0.032 atmC. 0.760 atmD. 166 atm |
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Answer» Correct Answer - B |
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