1.

For the reaction, P_((g))+3Q_((g))iff4R_((g)) Initial concentration of P is equal to that of Q. The equilibrium concentration of P and R are equal. K_(c) is equal to

Answer»

`0.08`
`0.8`
8
`(1)/(8)`

SOLUTION :Let initial concentration of P and Q are equal and at equilibrium x concentration of P reacts, then
`{:(,P_((g)),+,3Q_((g)),iff,4R_((g))),("Initial conc.",C,,C,,0),(("moles "L^(-1)),,,,,),("At equilibrium",(C-x),,(C-3x),,4x),("But it is given that",(C-x)=4x,,,,):}`
`therefore C=5x`
`K_(c)=([R]^(4))/([P][Q]^(3))=((4x)^(4))/((4x)(5x-3x)^(3))=(64X^(3))/(8x^(3))=8`


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