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For the reaction `PCl_(3(g))+Cl_(2(g))hArrPCl_(5(g))at 250^(@)C,` then value of `K_(c)` is 26, then the value of `K_(p)` the same temperaturee will beA. `0.61`B. `0.57`C. `0.83`D. `0.46` |
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Answer» Correct Answer - A `K_(p)=K_(c)(RT)^(Deltan)=26(0.0821xx523)^(-1)=0.61.` `Deltan_(g)=1-2=-1` |
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