1.

For the reaction R-X+OH^(-)toR-OH+X^(-1), the rate of reaction is given as, rate =4.7xx10^(-5)[R-X][OH^(-)]+0.24xx10^(-5)[RX]. What percentage of R-X react by S_(N)2 mechanism when [OH^(-)]=0.001 molar?

Answer»

1.9
4.7
2.8
4.9

Answer :A


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