For the reaction R-X+OH^(-)toR-OH+X^(-) the rate reaction is given as, – InterviewSolution

1.	For the reaction R-X+OH^(-)toR-OH+X^(-) the rate reaction is given as, rate=4.7xx10^(-5)[R-x][OH^(-)]+.024xx10^(-5)[RX] what percentage of R-X react by S_(N^(2)) mechanism when [OH^(-)]=0.001 molar.
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