1.

For the reaction RtoP ,the concentration of a reactant changes from 003 M to 0.02 M in 25 minutes.Calculate the average rate of reaction using units of time both in minutes and seconds.

Answer»

Solution :Given Reaction R`to`P for this reaction
AVERAGE rate `r_(AV)=-(Delta[R])/(Deltat)`
`Delta[R]=[R_(2)]-[R_(1)]` and `Deltat=(t_(2)-t_(1))` `THEREFORE` Average rate=`(0.01M)/(25 "minute")`
+`4.0xx10^(-4) mol L^(-1) m^(-1)`
The CALCULATION of rate in 1 second `Deltat=(t_(2)-t_(1))` `Delta[R]=(0.02-0.03) mol L^(-1)`
`=-0.01 mol L^(-1)`
So, average rate `r_(av)=-(Delta[R])/(Delta)`
`=-(-0.01 mol L^(-1))/(150s)`
`+6.667xx10^(-5) mol L^(-1) S^(-1)`
OR
`r_(av)=(r_(av)mol L^(-1) m^(-1)xx1M)/(60 s^(-1))`
`=(4.0xx10^(-4))/(60) mol L^(-1)s^(-1)`
`=6.667xx10^(-5) mol L^(-1) s^(-1)`


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