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For the reaction takes places at certain tempreature `NH_(4) HS(s) hArrNH_(3)(g) + H_(2)S(g)`, if eqilibrium pressure is X bar, then `Delta_(r) G^(@)` would beA. `-2RT ln X`B. `- RT ln (X- ln2)`C. `-2RT (ln X- ln2)`D. None of these |
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Answer» Correct Answer - C `DeltaG^(@) = - 2.303 RT log Keq` ` = - RT In K_(P)` `P_(NH^(3)) = P_(H_(2)S) = (x)/(2) "bar"` `= - RT ln (("x")/(2))^(2) = - 2RT (ln X - ln 2)` |
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