1.

For the reactionN_(2(g))+O_(2(g))hArr2NO_((g)), the equlibrium constant is K_(1),The equilibrium constant is K_(2) for the reaction 2NO_((g))+2_(2(g))hArr2NO_(2(g)). What is K for the reaction NO_(2(g))hArr1/2N_(2(g))+O_(2(g))

Answer»

`(1)/((K_(1)K_(2)))`
`(1)/((2K_(1)K_(2)))`
`(1)/((4K_(1)K_(2)))`
`[(1)/(K_(1)K_(2))]^(1//2)`

Solution :`N_(2(g))+O_(2(g))hArr2NO_((g)),K_(1)`
`(2NO_((g))+O_(2(g))hArr2NO_(2(g)),K_(2))/(N_(2(g))+2O_(2(g))hArr2NO_(2(g)),K=K_(1)xxK_(2))`
`THEREFORE"For"NO_(2(g))hArr1/2N_(2(g))+O_(2(g)),K'[(1)/(K_(1)K_(2))]^(1/2).`


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