1.

For the reactionPCl_(3(g))+Cl_(2(g))hArrPCl_(5(g))at 250^(@)C, then value of K_(c) is 26, then the value of K_(p) the same temperaturee will be

Answer»

<P>`0.61`
`0.57`
`0.83`
`0.46`

Solution :`K_(p)=K_(c)(RT)^(DELTAN)=26(0.0821xx523)^(-1)=0.61.`
`Deltan_(G)=1-2=-1`


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