For the reactions, `{:(AhArrB, K_(c)=2), (BhArrC, K_(c)=4), (ChArrD, K_(c)=6):}` `K_(c)` for the reaction, `AhArrD` is:A. `(2+4+6)`B. `(2xx4)//6`C. `(4xx6)//2`D. `2xx4xx6`

For the reactions, `{:(AhArrB, K_(c)=2), (BhArrC, K_(c)=4), (ChArrD, K

1.	For the reactions, `{:(AhArrB, K_(c)=2), (BhArrC, K_(c)=4), (ChArrD, K_(c)=6):}` `K_(c)` for the reaction, `AhArrD` is:A. `(2+4+6)`B. `(2xx4)//6`C. `(4xx6)//2`D. `2xx4xx6`
Answer» `2=([B])/([A])`, `4=([C])/([B])` and `6=([D])/([C])` Thus on multiplying, `2xx4xx6=([D])/([A])`, i.e., `K_(c)` for the reaction.

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For the reactions, `{:(AhArrB, K_(c)=2), (BhArrC, K_(c)=4), (ChArrD, K_(c)=6):}` `K_(c)` for the reaction, `AhArrD` is:A. `(2+4+6)`B. `(2xx4)//6`C. `(4xx6)//2`D. `2xx4xx6`

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