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For the redox change , `Zn_(s) + underset (0.1M)FuCu^2+ rarr underset(Zn^(2+))(1M) + Cu_((s))`, Taking place in a cell ` E_(cell)^@ ` is ` 1.10` volt . `E_(cell) ` for the cell would be :A. `1.07V`B. `0.82V`C. `2.14V`D. 180V |
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Answer» Correct Answer - A `E=E_(cell)^(0)+(0.059)/(2)log.([Cu^(2+)])/([Zn^(2+)])` `=1.10+(0.059)/(2)log.(0.1)/(1)=1.07V` |
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