1.

For the redox reaction MnO_(4)^(-)+C_(2)O_(4)^(-2)+H^(+) rarr Mn^(2+)+CO_(2)+H_(2)O the correct coefficients of the reactants for the balanced reaction are

Answer»

`{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+)),(2,5,16):}`
`{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+)),(16,5,2):}`
`{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+)),(5,16,2):}`
`{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+)),(2,16,5):}`

SOLUTION :`MnO_(4)^(-) + 8H^(+) + 5e^(-) rarr Mn^(2+) + 4H_(2) O xx 2`
`(c_(2)O_(4)^(2-) rarr 2 CO_(2) + 2e^(-) xx 5)/(2MnO_(4)^(-) + 5C_(2)O_(4)^(2-) + 16H^(+) rarr 2MN^(2+) + 10CO_(2) + 8H_(2)O)`
Thus the coefficient of `MnO_(4)^(-), C_(2)O_(4)^(2-) and H^(+)` in the abovve balanced equation respectively are 2, 5, 16


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