1.

For the redox reaction Zn_((s))+Cu^(2+)(0.1M)toZn^(2+)(1M)+Cu_((s)) taking place in a cell, E_(cell)^(o) is 1.10 volt, E_(cell) for the cell will be (2.303(RT)/(F)=0.0591)

Answer»

2.14 VOLT
1.80 volt
1.07 volt
0.82 volt

Solution :`E=E^(@)-(0.059)/(n)"log"([ZN^(++)])/([Cu^(++)])=1.10-(0.059)/(2)"log"(1)/(0.1)`
`=1.10-0.0295log10=1.07` volt


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