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For the reversible reaciton, N_(2(g))+3H_(2(g))hArr2NH_(3(g)) at 500^(@)C, the value of K_(p) is 1.44xx10^(-5) when partial pressure is measured in atmospheres. The conrresponding value of K_(c) with concentration in mole "littre"^(-1), is |
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Answer» `1.44xx10^(-5)//(0.082xx500)^(-2)` `Deltan=2-4=-2` `K_(p)=K_(c)[RT]^(Deltan),K_(p)=K_(c)[RT]^(-2)` `K_(c)=(K_(p))/([RT]^(-2))=(1.44xx10^(-5))/([0.082xx773]^(-2))` |
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