For the reversible reaction 2H_2S_((g)) hArr 2H_(2(g))+S_(2(g)) The – InterviewSolution

1.	For the reversible reaction 2H_2S_((g)) hArr 2H_(2(g))+S_(2(g)) The equilibrium concentrations, are [H_2S]=0.5 mole/litre [H_2]=0.4 mole/litre [S_2]=0.4 mole/litre The value of 'K' would be
Answer» `0.004` mole/litre `0.08` mole/litre `0.016` mole/litre `0.16` mole/litre Answer :C

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