1.

For the reversible reaction the initial concentrations of A and B are Am and bm,and the equillibrium concentrations are (a-x)M and (b+x) respectively. The value of x is:

Answer»

`(K_(1)a+K_(2)B)/(K_(1)+K_(2))`
`(K_(1)a-K_(2)b)/(K_(1)+K_(2))`
`(K_(1)+K_(2))/(K_(1)a+K_(2)b)`
`(K_(1)+K_(2))/(K_(1)a-K_(2)b)`

ANSWER :B


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