1.

For the situation shown in the figure, what should be the value of force required to move the rod with constant velocity v = 2 m/s ?

Answer»

`3.75xx10^(-3)` N
`3.75xx10^(-2)` N
`3.75xx10^2` N
`3.75xx10^4` N

SOLUTION :`epsilon=Bvl`
`THEREFORE I= (Bvl)/R`
Now, magnetic force
`F_m=BI L`
`=(B(Bvl))/R. l=(B^2vl^2)/R`
`therefore F_m=((0.15)^2xx2xx(0.50)^2)/3`
`=0.00375=3.75xx10^(-3)` N


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