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For the system `3A + 2BhArr` C, the expression for equilibrium constant isA. `([3A][2B])/(C)`B. `([C])/([3A][2B])`C. `([A]^(3) [B]^(2))/([C])`D. `([C])/([A]^(3) [B]^(2))` |
Answer» Correct Answer - D Equilibrium constant for the reaction, `3A + 2Bh C` is `K= ([C])/([A]^(3) [B]^(2))` |
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