1.

For the system A_((g))+2B_((g))hArrC_((g)), the equlibrium concentrations are (A) 0.06 mole/litre (B) 0.12 mole/litre (C ) 0.216 mole/litre. The K_(eq) for the reaction is

Answer»

250
416
`4XX10^(-3)`
125

Solution :For reaction `A+2BhArrC`
`K=([C])/([A][B]^(2))=(0.216)/(0.06xx0.12xx0.12)=250.`


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