For the system `A_((g))+2B_((g))hArrC_((g)),` the equlibrium concentrations are (A) `0.06` mole/litre (B) 0.12 mole/litre (C ) `0.216` mole/litre. The `K_(eq)` for the reaction isA. 250B. 416C. `4xx10^(-3)`D. 125

For the system `A_((g))+2B_((g))hArrC_((g)),` the equlibrium concentra

1.	For the system `A_((g))+2B_((g))hArrC_((g)),` the equlibrium concentrations are (A) `0.06` mole/litre (B) 0.12 mole/litre (C ) `0.216` mole/litre. The `K_(eq)` for the reaction isA. 250B. 416C. `4xx10^(-3)`D. 125
Answer» Correct Answer - A For reaction `A+2BhArrC` `K=([C])/([A][B]^(2))=(0.216)/(0.06xx0.12xx0.12)=250.`

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For the system `A_((g))+2B_((g))hArrC_((g)),` the equlibrium concentrations are (A) `0.06` mole/litre (B) 0.12 mole/litre (C ) `0.216` mole/litre. The `K_(eq)` for the reaction isA. 250B. 416C. `4xx10^(-3)`D. 125

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