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For the system A2(g)+B2(g)⇌2AB(g), △H=+5 kJ/mole. If the activation energy for the forward step is 100 kcal/mole. If graph of ln(kb) vs T is drawn then find the value of the slope at 500 K. (kb = rate constant of the backward reaction, take 1 cal = 4.2 J and the gas constant R = 8.3 J/molK)

Answer» For the system A2(g)+B2(g)2AB(g), H=+5 kJ/mole. If the activation energy for the forward step is 100 kcal/mole. If graph of ln(kb) vs T is drawn then find the value of the slope at 500 K. (kb = rate constant of the backward reaction, take 1 cal = 4.2 J and the gas constant R = 8.3 J/molK)


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