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For the vaporisation of water : `H_(2)O (I) hArr H_(2)O(g)` [1 atm. Pressure] Given : `Delta S = 120 JK^(-1)` and `Delta H =+45.0 kJ`. Evaluate the temperature at which liquid water and water vapour are in equilibrium at 1 atm. Pressure- |
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Answer» We know that : at equilibrium `Delta G = 0` `because " " Delta G = Delta H - T Delta S " " therefore " " T Delta S = Delta H rArr T=(Delta H)/(Delta S)=(45.0xx10^(3)J)/(120 JK^(-1))=375 K` |
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