1.

For two different acids with same concentration

Answer»

The relative strngth is expressed as `(alpha_(1))/(a_(2))`
Relative strength is expressed as `(K_(a_(1)))/(K_(a_(2)))`
Relative strength is expressed as `SQRT((K_(a_(1)))/(K_(a_(2))))`
`(pH_(1))/(pH_(2))`

Solution :Let `alpha_(1), and alpha_(2)` be the degree of dissociation of TWO acids and `alpha_(1),alpha_(2)` are very small when compared to unity.
`(calpha_(1)^(2))/(1-alpha_(1))=K_(a_(1)),(calpha_(2)^(2))/(1-alpha_(2))=K_(a_(2))impliessqrt((K_(a_(1)))/(K_(a_(2))))=(alpha_(1))/(alpha_(2))=` relative strength
Hence choices (a) and (B) and (c) are correct while (b) and (d) are incorrect.


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