For two independent events A and B, P(B|A) = \(\frac{1}{2}\) and P(A

1.	For two independent events A and B, P(B\|A) = \(\frac{1}{2}\) and P(A ∩ B) = \(\frac{1}{5}\). Find P(A).
Answer» P(B\|A) = \(\frac{1}{2}\), P(A ∩ B) = \(\frac{1}{5}\), P(A) = ? P(B\|A) = \(\frac{P(A∩B)}{P(A)}\) ∴ 12 = \(\frac{\frac{1}{5}}{P(A)}\) ∴ \(\frac{1}{2}p(A) = \frac{1}{5}\) ∴ P(A) = \(\frac{1}{5}\times2=\frac{2}{5}\)

For two independent events A and B, P(B|A) = \(\frac{1}{2}\) and P(A ∩ B) = \(\frac{1}{5}\). Find P(A).

Answer»

P(B|A) = \(\frac{1}{2}\), P(A ∩ B) = \(\frac{1}{5}\), P(A) = ?

P(B|A) = \(\frac{P(A∩B)}{P(A)}\)

∴ 12 = \(\frac{\frac{1}{5}}{P(A)}\)

∴ \(\frac{1}{2}p(A) = \frac{1}{5}\)

∴ P(A) = \(\frac{1}{5}\times2=\frac{2}{5}\)

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For two independent events A and B, P(B|A) = \(\frac{1}{2}\) and P(A ∩ B) = \(\frac{1}{5}\). Find P(A).

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