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For unknown reaction half mole of reactant of total 2 moles reactant is converted in to product time is taken 1 hour.Then calculate how many moles of reactant is present after 4 hours? |
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Answer» 0.225 MOLE After 1 hour `(1)/(1)` mole `t_((1)/(2))`=1Hour so After 2 hour 0.5 mole `therefore` every `t_((1)/(2))` time After 3 hour 0.250mole After 4 hour 0.125 mole |
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