1.

For vaporization of water at 1 atmospheric pressure, the values of DeltaH and DeltaS are 40.63 kJ mol^(-1) and 108.8 JK^(-1)mol^(-1), respectively. The temperature when Gibbs energy change (DeltaG) for this transformation will be zero, is

Answer»

273.4 K
393.4 K
373.4 K
293.4 K

Solution :`DeltaG=DeltaH-TDeltaS`
`DeltaG=0`
`DeltaH=TDeltaS`,
`T=(40.63xx10^(3))/(108.8)=373.4 K`.


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