1.

For what distance is ray optics a good approximation when the aperture is 4mm wide and the wavelength is 500 nm ?

Answer»

32m
64m
16m
8m

Solution :Fresnel.s distance `Z_(F)=(a^(2))/(lamda)=((4mm)^(2))/((500nm))=((4XX10^(-3)m)^(2))/((500xx10^(-9)m))=32m`.


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