InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
For what value of k is the followinf function continuous at x = `-pi/6`. Where `f(x) = (sqrt3 sin x + cos x)/( x + pi/6) , x != -pi/6 and f(x) = k, x = - pi/6` |
|
Answer» `lim_(x->a^+)f(x)=f(a)=lim_(x->0^-)f(x)` `lim_(x->-pi/6^+)(sqrt3sinx+cosx)/(x+pi/6)` `lim_(x->-pi/6^+)(sqrt3/2sinx+cosx*1/2)^2/(x+pi/6)` `lim_(h->0)(sinh/h)*2=2` `f(-pi/6)=2`. |
|