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For what value of n are the nth term of the following two A.P's the same. Also find this term 63, 65, 67, ... and 3, 10, 17, .... |
Answer» 1st AP = 63, 65, 67, ... Here, a = 63, d = 65 – 63 = 2 and 2nd AP = 3, 10, 17, ... Here, a = 3, d = 10 – 3 = 7 According to the question, 63 + (n – 1)2 = 3 + (n – 1)7 ⇒ 63 + 2n – 2 = 3 + 7n – 7 ⇒ 61 + 2n = 7n – 4 ⇒ 65 = 7n – 2n ⇒ 5n = 65 ⇒ n = 13 13th term of the given AP’s are same. Now, we will find the 13th term We have, an = a + (n – 1)d a13 = 63 + (13 – 1)2 a13 = 63 + 12 × 2 a13 = 63 + 24 a13 = 87 |
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