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For what value of x are the points (1,5), (x,1) and (4,11) collinear?1. 12. 23. 34. -1 |
Answer» Correct Answer - Option 4 : -1 Calculation: Area of the triangle formed by given points = \(\frac{1}{2}\) |1(1-11) + x(11-5) + 4(5-1)| = \(\frac{1}{2}\)|6x + 6| = 3 |x + 1| The given points are collinear iff area of triangle = 0 i.e, iff 3 |x + 1| = 0 i.e, x + 1 = 0 iff x = -1 Hence the required value of x is -1.
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