1.

Three forces P, Q, R are acting at a point in a plane. The angle between P and Q, Q and R are 150° and 120° respectively, then for equilibrium, forces P, Q, R are in the ratio1. 1 ∶ 2 ∶ 32. 1 ∶ 2 ∶ √3 3. 3 ∶ 2 ∶ 14. √3 ∶ 2 ∶ 1

Answer» Correct Answer - Option 4 : √3 ∶ 2 ∶ 1

For equilibrium:

\(\dfrac{P}{\sin p} =\dfrac{Q}{\sin q} = \dfrac{R}{\sin r}\)

Where,

p = Angle between Q and R = 120° 

r = Angle between P and Q = 150° 

q = Angle between P & R = 360° - (120° + 150°)

= 90° 

hence,

P ∶ Q ∶ R = sin p ∶ sin q ∶ sin r

= sin 120° ∶ sin 90° ∶ sin 150° 

\(=\dfrac{\sqrt{3}}{2} : \dfrac{1}{2} : \dfrac{1}{1}\)

\(\therefore \sqrt{3} : 1 : 2\)



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