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Three forces P, Q, R are acting at a point in a plane. The angle between P and Q, Q and R are 150° and 120° respectively, then for equilibrium, forces P, Q, R are in the ratio1. 1 ∶ 2 ∶ 32. 1 ∶ 2 ∶ √3 3. 3 ∶ 2 ∶ 14. √3 ∶ 2 ∶ 1 |
Answer» Correct Answer - Option 4 : √3 ∶ 2 ∶ 1 For equilibrium: \(\dfrac{P}{\sin p} =\dfrac{Q}{\sin q} = \dfrac{R}{\sin r}\) Where, p = Angle between Q and R = 120° r = Angle between P and Q = 150° q = Angle between P & R = 360° - (120° + 150°) = 90° hence, P ∶ Q ∶ R = sin p ∶ sin q ∶ sin r = sin 120° ∶ sin 90° ∶ sin 150° \(=\dfrac{\sqrt{3}}{2} : \dfrac{1}{2} : \dfrac{1}{1}\) \(\therefore \sqrt{3} : 1 : 2\) |
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