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For what values of p are 2p + 1, 13, 5p – 3 are three consecutive terms of an A.P.? |
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Answer» Given: 2p + 1, 13, 5p – 3 are three consecutive terms of an A.P. To find: The value of p Solution: Consider a1 = 2p + 1 , a2 = 13 and a3 = 5p – 3 The A.P will be of the form 2p + 1, 13, 5p – 3,......... Since the terms are in A.P so the common differences in them is same. ⇒ a2 - a1 = a3 - a2 ⇒ 13– (2p + 1) = 5p –3 –13 ⇒ 13– 2p - 1 = 5p –3 –13 ⇒12– 2p = 5p –16 ⇒12+16 = 5p +2p ⇒ 28 = 7p ⇒ p= 4 |
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