1.

For which combination of working temperatures of source and sink the efficiency of Carnot's heat engine is maximum?

Answer»

600 K, 400 K
400 K, 200 K
500 K, 300 K
300 K, 100 K

Solution :The efficiency of Carnot.s heat engine, `eta =(T_(1)-T_(2))/(T_(1))`
For given combinations
`eta_(1)=(1)/(3), eta_(2)=(1)/(2), eta_(3)=(2)/(5), eta_(4)=(2)/(3)`
So, it is maximum for
`T_(1)=300 K and T_(2)=100 K`
So, correct CHOICE is (d).


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