1.

For which combination of working temperatures, the efficiency of 'Carnot's engine' is the least?

Answer»

60 K, 40 K
40 K, 20 K
80 K, 60 K
100 K, 80 K

Solution :We know that,
`eta = (1-(T_(L))/(T_(H)))XX100`
According to trial and error method
`eta=(1-(80)/(100))xx100`
`eta = ((100-80)/(100))xx100`
`eta = (20)/(100)xx100=20%`


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