1.

For x != 0, 1, define f_(1)(x)=x, f_(2)(x)=1/x, f_(3)(x)=1-x, f(5) (x)=(x-1)//x, f_(6)(x)=x//(x-1) This family of functions is closed under composition that is , the composition of any two of these functions is again one of these. Let H be a function such that f_(4)OH=f_(5). Then H is equal to

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`f_(1)`
`f_(2)`
`f_(3)`
`f_(4)`

Answer :D


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