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For `x^2-(a+3)|x|=4=0`to have real solutions, the range of `a`is`(-oo,-7]uu[1,oo)``(-3,oo)``(-oo,-7]``[1,oo)`A. `(-oo,-7]cup [1,oo)`B. `(-3,oo)`C. `(-oo,-7]`D. `[1,oo)` |
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Answer» Correct Answer - D `a = (x^(2) + 4)/(|x|) - 3` `= |x| + (4)/(|x|) - 3` `ge 2 sqrt(|x| xx (4)/(|x|)) - 3` `implies a ge 1` |
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