1.

Fora certainreactionDelta H^(@) =- 224 kJand Delta S^(@) =- 153 JK Atwhattemperaturewill itchangefromspontaneous tonon-spontaneous ?

Answer»


SOLUTION :GIVEN :`DELTA H^(@) =- 224 kJ = 224000 J`
`Delta S^(@)= - 153 JK^(-1)`
Temperature(T)at whichreactionchangesfromspontaneousto non- spontaneous = ?
Find thetemperatureat eqilibriumwhere `Delta G^(@) = 0`
`Delta G^(@)= Delta H^(@) - T Delta S^(@)`
`0 = Delta H^(@)- T Delta S^(@)`
`:. T Delta S^(@)= Delta H^(@)`
`:.T = (Delta H^(@))/(Delta S^(@)) = (224000)/(153)= 1465 K`
Hencereactionwill bespontaneousbelow1465 K. It WILLBE atequilibriumat 1464 Kand non- spontaneousabove 1464 K.


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