1.

Foran exothermicreactionanactivationenergyof 70 KJ"mole " ^(-1 )andtheenthalpychangeofreactionis 30 KJ"mole" ^(-1). Theorderofthereactionis

Answer»

`70KJ"MOLE"^(-1)`
`30 KJ"mole "^(-1)`
`40 KJ "mole" ^(-1)`
`100 KJ"mole "^(-1)`

Solution :`Delta H=E_(a)-E_(a)^(r ) therefore-30 =70 -E_(a )^(r ).thereforeE_(a)^(r ) = 100 `


Discussion

No Comment Found