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Force acting on a particle moving along x-axis as shown in figure. Find points of stable and unstable equlibrium. . |
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Answer» Correct Answer - A::B::C::D At `A,x=0` and `F=0` For `xgt0, F= + ve` i.e. force is in the direction of displacement. Hence A is unstable equilibrium position. same concept can be applied with E also. At point `C,F =0` for`xgtx_C , F = -ve` Displacement is positive and force is negative (in oppsite direction of displacement). therefore, C point is stable equilibrium point. |
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