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Force of attraction between two point electric charges placed at a distance `d` in a medium is `F`. What distance apart should these be kept in the same medium, so that force between them becomes `F//3`?A. `2sqrt(3)d`B. `3d`C. `9d`D. `sqrt(3)d` |
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Answer» Correct Answer - d Let `q_(1)` and `q_(2)` be the two point charges. Then, force between the charges, when kept at a distance `d` apart, `F=(1)/(4piepsilon_(0))*(q_(1)q_(2))/(d^(2))` Suppose that force between the two charges becomes `F//3`, when the charges are kept at a distance `x` apart. Then `(1)/(4pi epsilon)*(q_(1)q_(2))/(x^(2))=F/3` or `1/(4piepsilon_(0))*(q_(1)q_(2))/(x^(2))=1/3(1/(4piepsilon_(0))*(q_(1)q_(2))/(d^(2)))` Or `x= sqrt(3)d` |
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