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Form a quadratic equation with real coefficients whose one root is `3-2idot` |
Answer» Since the complex roots always occur in conjugate pairs, so the other root is 3 + 2i. The sum of the roots is (3+ 2i) + 3 - 2i) = 6 . The product of the roots is `(3 + 2i) (3 - 2i) = 9-4i^(2) = 9 + 4 = 13` Hence, the equation is `x^(2) -Sx + P = 0` `rArr x^(2) - 6x + 13 = 0` |
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