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Form the differential equation from the following primitives where constants are arbitrary:y = ax2 + bx + c |
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Answer» As the given equation has 3 different arbitrary constants so we can differentiate it thrice with respect to x So, differentiating once with respect to x, \(\frac{dy}{dx} = 2ax + b\) Differentiating twice with respect to x, \(\left(\frac{d^2y}{dx^2}\right)=2a\) Now, differentiating thrice with respect to x we get, \(\frac{d^3y}{dx^3}=0\) Hence, \(\frac{d^3y}{dx^3}=0\) is the differential equation corresponding to y = ax2 + bx + c. |
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