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Form the differential equation having `y=(sin^(-1) x)^2 +A cos^(-1) x +B` where A and B are arbitrary constants, as its general solution |
Answer» `y = (sin^-1x)^2+Acos^-1x+B` `=>dy/dx = 2sin^-1x(1/sqrt(1-x^2))+A(-1/(sqrt(1-x^2)))` `=>dy/dx = (2sin^-1x-A)(1/sqrt(1-x^2))` `=>dy/dx(sqrt(1-x^2)) = (2sin^-1x-A)` `=>A = 2sin^-1x-dy/dx(sqrt(1-x^2)) ` Again differentiating w.r.t. `x`, `=>0 = 2(1/sqrt(1-x^2)) -dy/dx(1/(2sqrt(1-x^2)))(-2x) - sqrt(1-x^2)(d^2y)/dx^2)` `=>2 +xdy/dx -(1-x^2)(d^2y)/dx^2 = 0` `=>(1-x^2)(d^2y)/dx^2 -xdy/dx-2 = 0`, which is the required differential equation. |
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