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Form the differential equation representing the family of curves given by `(x-a)^2+2y^2=a^2`, where a is an arbitrary constant. |
Answer» Given, family of curve, `(x-a)^(2)+2y^(2)=a^(2)`, where `a` is constant. `implies x^(2)-2ax+2y^(2)=0`……`(1)` Differentiate w.r.t.x, `2x-2a+4y(dy)/(dx)=0`…….`(2)` Multiply equation `(2)` by `x` and subtract equation `(1)` from it, `x(2x-2a+4y(dy)/(dx))-(x^(2)-2ax+2y^(2))=0` `2x^(2)-2ax+4xy(dy)/(dx)-x^(2)+2ax-2y^(2)=0` `implies 4xy(dy)/(dx)+x^(2)-2y^(2)=0` `implies (dy)/(dx)=(2y^(2)-x^(2))/(4xy)` which is the required differential equation. |
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