1.

Formation of polyethylene from calcium carbide takes place as follows CaC_2+2H_2O to Ca(OH)_2 +C_2H_2 C_2H_2 +H_2 to C_2H_4 n(C_2H_4) to (-CH_2-CH_2-)_n The amount of polyethylene obtained from 64.1 kg CaC_2 is

Answer»

7 kg
14 kg
21 kg
28 kg

Solution :`underset"64 G"(CaC_2)+2H_2O to Ca(OH)_2+C_2H_2`
`C_2H_2+H_2 to underset"28 g"(C_2H_4)`
64g of `CaC_2` GIVES 28 g of ethylene
`therefore` 64 kg of `CaC_2` will give 28 kg of polyethylene


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