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Formation of polyethylene from calcium carbide takes place as follows CaC_2+2H_2O to Ca(OH)_2 +C_2H_2 C_2H_2 +H_2 to C_2H_4 n(C_2H_4) to (-CH_2-CH_2-)_n The amount of polyethylene obtained from 64.1 kg CaC_2 is |
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Answer» 7 kg `C_2H_2+H_2 to underset"28 g"(C_2H_4)` 64g of `CaC_2` GIVES 28 g of ethylene `therefore` 64 kg of `CaC_2` will give 28 kg of polyethylene |
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