1.

Formulate the compound tetraammineaquachloridocobalt (III) chloride

Answer»

Solution :Anion (simple ion) `=Cl^(-)`
for the COORDINATION ENTITY, writing FIRST the symbol for metal atom and then the ligands in the alphabetical order, we have
Cation (complex ion) `=[Co(NH_(3))_(4)(H_(2)O)Cl]^(x)` where x is the charge on the complex ion.
x = oxidation state to cobalt + charge on the ligands
x=+3+0+0+(-1)=+2
(`H_(2)O` and `NH_(3)` are neutral group and carry no charge. Only chlorido group carries charge = - 1)
Charge on one anion = - 1
Charge on complex cation = + 2
Clearly, two anions will NEUTRALISE the charge of the cation.
Hence, formula of the given compound is `[Co(NH_(3))_(4)(H_(2)O)Cl]Cl_(2)`.


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