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Fot the reaction A + B to produts, it is found that orders of the reaction in A and B are 1 and 2 respectively. When the conc. ofA is halved and that of B is doubled, the rate increases by a factor : |
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Answer» 2 `(dx)/(dt)=r_1=k[A][B]^2`… (i) `r_2 = k[1/2][2B]^2`…(ii) `or r_2= 1/2xx2^2k[A][B]^2`…(iii) Dividing (iii) by (i) `(r_(2))/(r_(1)) = (2 k [A][B]^(2))/(k[A][B]^(2)) = 2 therefore r_(2) = 2r_(1)` |
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