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Four bodies A,B,C and D are projected with equal velocities having angles of projection `15^(@),30^(@),45^(@) and 60^(@)` with the horizontal respectively. The body having the shortest range isA. AB. BC. CD. D |
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Answer» Correct Answer - a Range, `R=(u^(2)sin 2 theta)/g` For a given initial velocity `R prop sin 2 theta` `R_(2)=(u^(2)sin (90^(@)+2 theta))/g=(u^(2)cos 2 theta)/g=R_(1)` |
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